Optimal. Leaf size=577 \[ \frac{2 \sqrt{2} g^2 \sqrt{b^2-a^2} \sqrt{\cos (e+f x)} \Pi \left (-\frac{a}{b-\sqrt{b^2-a^2}};\left .\sin ^{-1}\left (\frac{\sqrt{d \sin (e+f x)}}{\sqrt{d} \sqrt{\cos (e+f x)+1}}\right )\right |-1\right )}{a b \sqrt{d} f \sqrt{g \cos (e+f x)}}-\frac{2 \sqrt{2} g^2 \sqrt{b^2-a^2} \sqrt{\cos (e+f x)} \Pi \left (-\frac{a}{b+\sqrt{b^2-a^2}};\left .\sin ^{-1}\left (\frac{\sqrt{d \sin (e+f x)}}{\sqrt{d} \sqrt{\cos (e+f x)+1}}\right )\right |-1\right )}{a b \sqrt{d} f \sqrt{g \cos (e+f x)}}+\frac{g^2 \sqrt{\sin (2 e+2 f x)} F\left (\left .e+f x-\frac{\pi }{4}\right |2\right )}{a f \sqrt{d \sin (e+f x)} \sqrt{g \cos (e+f x)}}+\frac{g^{3/2} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt{g} \sqrt{d \sin (e+f x)}}{\sqrt{d} \sqrt{g \cos (e+f x)}}\right )}{\sqrt{2} b \sqrt{d} f}-\frac{g^{3/2} \tan ^{-1}\left (\frac{\sqrt{2} \sqrt{g} \sqrt{d \sin (e+f x)}}{\sqrt{d} \sqrt{g \cos (e+f x)}}+1\right )}{\sqrt{2} b \sqrt{d} f}-\frac{g^{3/2} \log \left (-\frac{\sqrt{2} \sqrt{g} \sqrt{d \sin (e+f x)}}{\sqrt{g \cos (e+f x)}}+\sqrt{d} \tan (e+f x)+\sqrt{d}\right )}{2 \sqrt{2} b \sqrt{d} f}+\frac{g^{3/2} \log \left (\frac{\sqrt{2} \sqrt{g} \sqrt{d \sin (e+f x)}}{\sqrt{g \cos (e+f x)}}+\sqrt{d} \tan (e+f x)+\sqrt{d}\right )}{2 \sqrt{2} b \sqrt{d} f} \]
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Rubi [A] time = 0.972302, antiderivative size = 577, normalized size of antiderivative = 1., number of steps used = 18, number of rules used = 14, integrand size = 37, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.378, Rules used = {2900, 2838, 2573, 2641, 2574, 297, 1162, 617, 204, 1165, 628, 2908, 2907, 1218} \[ \frac{2 \sqrt{2} g^2 \sqrt{b^2-a^2} \sqrt{\cos (e+f x)} \Pi \left (-\frac{a}{b-\sqrt{b^2-a^2}};\left .\sin ^{-1}\left (\frac{\sqrt{d \sin (e+f x)}}{\sqrt{d} \sqrt{\cos (e+f x)+1}}\right )\right |-1\right )}{a b \sqrt{d} f \sqrt{g \cos (e+f x)}}-\frac{2 \sqrt{2} g^2 \sqrt{b^2-a^2} \sqrt{\cos (e+f x)} \Pi \left (-\frac{a}{b+\sqrt{b^2-a^2}};\left .\sin ^{-1}\left (\frac{\sqrt{d \sin (e+f x)}}{\sqrt{d} \sqrt{\cos (e+f x)+1}}\right )\right |-1\right )}{a b \sqrt{d} f \sqrt{g \cos (e+f x)}}+\frac{g^2 \sqrt{\sin (2 e+2 f x)} F\left (\left .e+f x-\frac{\pi }{4}\right |2\right )}{a f \sqrt{d \sin (e+f x)} \sqrt{g \cos (e+f x)}}+\frac{g^{3/2} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt{g} \sqrt{d \sin (e+f x)}}{\sqrt{d} \sqrt{g \cos (e+f x)}}\right )}{\sqrt{2} b \sqrt{d} f}-\frac{g^{3/2} \tan ^{-1}\left (\frac{\sqrt{2} \sqrt{g} \sqrt{d \sin (e+f x)}}{\sqrt{d} \sqrt{g \cos (e+f x)}}+1\right )}{\sqrt{2} b \sqrt{d} f}-\frac{g^{3/2} \log \left (-\frac{\sqrt{2} \sqrt{g} \sqrt{d \sin (e+f x)}}{\sqrt{g \cos (e+f x)}}+\sqrt{d} \tan (e+f x)+\sqrt{d}\right )}{2 \sqrt{2} b \sqrt{d} f}+\frac{g^{3/2} \log \left (\frac{\sqrt{2} \sqrt{g} \sqrt{d \sin (e+f x)}}{\sqrt{g \cos (e+f x)}}+\sqrt{d} \tan (e+f x)+\sqrt{d}\right )}{2 \sqrt{2} b \sqrt{d} f} \]
Antiderivative was successfully verified.
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Rule 2900
Rule 2838
Rule 2573
Rule 2641
Rule 2574
Rule 297
Rule 1162
Rule 617
Rule 204
Rule 1165
Rule 628
Rule 2908
Rule 2907
Rule 1218
Rubi steps
\begin{align*} \int \frac{(g \cos (e+f x))^{3/2}}{\sqrt{d \sin (e+f x)} (a+b \sin (e+f x))} \, dx &=\frac{g^2 \int \frac{b-a \sin (e+f x)}{\sqrt{g \cos (e+f x)} \sqrt{d \sin (e+f x)}} \, dx}{a b}+\frac{\left (\left (a^2-b^2\right ) g^2\right ) \int \frac{\sqrt{d \sin (e+f x)}}{\sqrt{g \cos (e+f x)} (a+b \sin (e+f x))} \, dx}{a b d}\\ &=\frac{g^2 \int \frac{1}{\sqrt{g \cos (e+f x)} \sqrt{d \sin (e+f x)}} \, dx}{a}-\frac{g^2 \int \frac{\sqrt{d \sin (e+f x)}}{\sqrt{g \cos (e+f x)}} \, dx}{b d}+\frac{\left (\left (a^2-b^2\right ) g^2 \sqrt{\cos (e+f x)}\right ) \int \frac{\sqrt{d \sin (e+f x)}}{\sqrt{\cos (e+f x)} (a+b \sin (e+f x))} \, dx}{a b d \sqrt{g \cos (e+f x)}}\\ &=-\frac{\left (2 g^3\right ) \operatorname{Subst}\left (\int \frac{x^2}{d^2+g^2 x^4} \, dx,x,\frac{\sqrt{d \sin (e+f x)}}{\sqrt{g \cos (e+f x)}}\right )}{b f}+\frac{\left (2 \sqrt{2} \left (a^2-b^2\right ) \left (1-\frac{b}{\sqrt{-a^2+b^2}}\right ) g^2 \sqrt{\cos (e+f x)}\right ) \operatorname{Subst}\left (\int \frac{1}{\left (\left (b-\sqrt{-a^2+b^2}\right ) d+a x^2\right ) \sqrt{1-\frac{x^4}{d^2}}} \, dx,x,\frac{\sqrt{d \sin (e+f x)}}{\sqrt{1+\cos (e+f x)}}\right )}{a b f \sqrt{g \cos (e+f x)}}+\frac{\left (2 \sqrt{2} \left (a^2-b^2\right ) \left (1+\frac{b}{\sqrt{-a^2+b^2}}\right ) g^2 \sqrt{\cos (e+f x)}\right ) \operatorname{Subst}\left (\int \frac{1}{\left (\left (b+\sqrt{-a^2+b^2}\right ) d+a x^2\right ) \sqrt{1-\frac{x^4}{d^2}}} \, dx,x,\frac{\sqrt{d \sin (e+f x)}}{\sqrt{1+\cos (e+f x)}}\right )}{a b f \sqrt{g \cos (e+f x)}}+\frac{\left (g^2 \sqrt{\sin (2 e+2 f x)}\right ) \int \frac{1}{\sqrt{\sin (2 e+2 f x)}} \, dx}{a \sqrt{g \cos (e+f x)} \sqrt{d \sin (e+f x)}}\\ &=\frac{2 \sqrt{2} \sqrt{-a^2+b^2} g^2 \sqrt{\cos (e+f x)} \Pi \left (-\frac{a}{b-\sqrt{-a^2+b^2}};\left .\sin ^{-1}\left (\frac{\sqrt{d \sin (e+f x)}}{\sqrt{d} \sqrt{1+\cos (e+f x)}}\right )\right |-1\right )}{a b \sqrt{d} f \sqrt{g \cos (e+f x)}}-\frac{2 \sqrt{2} \sqrt{-a^2+b^2} g^2 \sqrt{\cos (e+f x)} \Pi \left (-\frac{a}{b+\sqrt{-a^2+b^2}};\left .\sin ^{-1}\left (\frac{\sqrt{d \sin (e+f x)}}{\sqrt{d} \sqrt{1+\cos (e+f x)}}\right )\right |-1\right )}{a b \sqrt{d} f \sqrt{g \cos (e+f x)}}+\frac{g^2 F\left (\left .e-\frac{\pi }{4}+f x\right |2\right ) \sqrt{\sin (2 e+2 f x)}}{a f \sqrt{g \cos (e+f x)} \sqrt{d \sin (e+f x)}}+\frac{g^2 \operatorname{Subst}\left (\int \frac{d-g x^2}{d^2+g^2 x^4} \, dx,x,\frac{\sqrt{d \sin (e+f x)}}{\sqrt{g \cos (e+f x)}}\right )}{b f}-\frac{g^2 \operatorname{Subst}\left (\int \frac{d+g x^2}{d^2+g^2 x^4} \, dx,x,\frac{\sqrt{d \sin (e+f x)}}{\sqrt{g \cos (e+f x)}}\right )}{b f}\\ &=\frac{2 \sqrt{2} \sqrt{-a^2+b^2} g^2 \sqrt{\cos (e+f x)} \Pi \left (-\frac{a}{b-\sqrt{-a^2+b^2}};\left .\sin ^{-1}\left (\frac{\sqrt{d \sin (e+f x)}}{\sqrt{d} \sqrt{1+\cos (e+f x)}}\right )\right |-1\right )}{a b \sqrt{d} f \sqrt{g \cos (e+f x)}}-\frac{2 \sqrt{2} \sqrt{-a^2+b^2} g^2 \sqrt{\cos (e+f x)} \Pi \left (-\frac{a}{b+\sqrt{-a^2+b^2}};\left .\sin ^{-1}\left (\frac{\sqrt{d \sin (e+f x)}}{\sqrt{d} \sqrt{1+\cos (e+f x)}}\right )\right |-1\right )}{a b \sqrt{d} f \sqrt{g \cos (e+f x)}}+\frac{g^2 F\left (\left .e-\frac{\pi }{4}+f x\right |2\right ) \sqrt{\sin (2 e+2 f x)}}{a f \sqrt{g \cos (e+f x)} \sqrt{d \sin (e+f x)}}-\frac{g \operatorname{Subst}\left (\int \frac{1}{\frac{d}{g}-\frac{\sqrt{2} \sqrt{d} x}{\sqrt{g}}+x^2} \, dx,x,\frac{\sqrt{d \sin (e+f x)}}{\sqrt{g \cos (e+f x)}}\right )}{2 b f}-\frac{g \operatorname{Subst}\left (\int \frac{1}{\frac{d}{g}+\frac{\sqrt{2} \sqrt{d} x}{\sqrt{g}}+x^2} \, dx,x,\frac{\sqrt{d \sin (e+f x)}}{\sqrt{g \cos (e+f x)}}\right )}{2 b f}-\frac{g^{3/2} \operatorname{Subst}\left (\int \frac{\frac{\sqrt{2} \sqrt{d}}{\sqrt{g}}+2 x}{-\frac{d}{g}-\frac{\sqrt{2} \sqrt{d} x}{\sqrt{g}}-x^2} \, dx,x,\frac{\sqrt{d \sin (e+f x)}}{\sqrt{g \cos (e+f x)}}\right )}{2 \sqrt{2} b \sqrt{d} f}-\frac{g^{3/2} \operatorname{Subst}\left (\int \frac{\frac{\sqrt{2} \sqrt{d}}{\sqrt{g}}-2 x}{-\frac{d}{g}+\frac{\sqrt{2} \sqrt{d} x}{\sqrt{g}}-x^2} \, dx,x,\frac{\sqrt{d \sin (e+f x)}}{\sqrt{g \cos (e+f x)}}\right )}{2 \sqrt{2} b \sqrt{d} f}\\ &=\frac{2 \sqrt{2} \sqrt{-a^2+b^2} g^2 \sqrt{\cos (e+f x)} \Pi \left (-\frac{a}{b-\sqrt{-a^2+b^2}};\left .\sin ^{-1}\left (\frac{\sqrt{d \sin (e+f x)}}{\sqrt{d} \sqrt{1+\cos (e+f x)}}\right )\right |-1\right )}{a b \sqrt{d} f \sqrt{g \cos (e+f x)}}-\frac{2 \sqrt{2} \sqrt{-a^2+b^2} g^2 \sqrt{\cos (e+f x)} \Pi \left (-\frac{a}{b+\sqrt{-a^2+b^2}};\left .\sin ^{-1}\left (\frac{\sqrt{d \sin (e+f x)}}{\sqrt{d} \sqrt{1+\cos (e+f x)}}\right )\right |-1\right )}{a b \sqrt{d} f \sqrt{g \cos (e+f x)}}-\frac{g^{3/2} \log \left (\sqrt{d}-\frac{\sqrt{2} \sqrt{g} \sqrt{d \sin (e+f x)}}{\sqrt{g \cos (e+f x)}}+\sqrt{d} \tan (e+f x)\right )}{2 \sqrt{2} b \sqrt{d} f}+\frac{g^{3/2} \log \left (\sqrt{d}+\frac{\sqrt{2} \sqrt{g} \sqrt{d \sin (e+f x)}}{\sqrt{g \cos (e+f x)}}+\sqrt{d} \tan (e+f x)\right )}{2 \sqrt{2} b \sqrt{d} f}+\frac{g^2 F\left (\left .e-\frac{\pi }{4}+f x\right |2\right ) \sqrt{\sin (2 e+2 f x)}}{a f \sqrt{g \cos (e+f x)} \sqrt{d \sin (e+f x)}}-\frac{g^{3/2} \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1-\frac{\sqrt{2} \sqrt{g} \sqrt{d \sin (e+f x)}}{\sqrt{d} \sqrt{g \cos (e+f x)}}\right )}{\sqrt{2} b \sqrt{d} f}+\frac{g^{3/2} \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1+\frac{\sqrt{2} \sqrt{g} \sqrt{d \sin (e+f x)}}{\sqrt{d} \sqrt{g \cos (e+f x)}}\right )}{\sqrt{2} b \sqrt{d} f}\\ &=\frac{g^{3/2} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt{g} \sqrt{d \sin (e+f x)}}{\sqrt{d} \sqrt{g \cos (e+f x)}}\right )}{\sqrt{2} b \sqrt{d} f}-\frac{g^{3/2} \tan ^{-1}\left (1+\frac{\sqrt{2} \sqrt{g} \sqrt{d \sin (e+f x)}}{\sqrt{d} \sqrt{g \cos (e+f x)}}\right )}{\sqrt{2} b \sqrt{d} f}+\frac{2 \sqrt{2} \sqrt{-a^2+b^2} g^2 \sqrt{\cos (e+f x)} \Pi \left (-\frac{a}{b-\sqrt{-a^2+b^2}};\left .\sin ^{-1}\left (\frac{\sqrt{d \sin (e+f x)}}{\sqrt{d} \sqrt{1+\cos (e+f x)}}\right )\right |-1\right )}{a b \sqrt{d} f \sqrt{g \cos (e+f x)}}-\frac{2 \sqrt{2} \sqrt{-a^2+b^2} g^2 \sqrt{\cos (e+f x)} \Pi \left (-\frac{a}{b+\sqrt{-a^2+b^2}};\left .\sin ^{-1}\left (\frac{\sqrt{d \sin (e+f x)}}{\sqrt{d} \sqrt{1+\cos (e+f x)}}\right )\right |-1\right )}{a b \sqrt{d} f \sqrt{g \cos (e+f x)}}-\frac{g^{3/2} \log \left (\sqrt{d}-\frac{\sqrt{2} \sqrt{g} \sqrt{d \sin (e+f x)}}{\sqrt{g \cos (e+f x)}}+\sqrt{d} \tan (e+f x)\right )}{2 \sqrt{2} b \sqrt{d} f}+\frac{g^{3/2} \log \left (\sqrt{d}+\frac{\sqrt{2} \sqrt{g} \sqrt{d \sin (e+f x)}}{\sqrt{g \cos (e+f x)}}+\sqrt{d} \tan (e+f x)\right )}{2 \sqrt{2} b \sqrt{d} f}+\frac{g^2 F\left (\left .e-\frac{\pi }{4}+f x\right |2\right ) \sqrt{\sin (2 e+2 f x)}}{a f \sqrt{g \cos (e+f x)} \sqrt{d \sin (e+f x)}}\\ \end{align*}
Mathematica [C] time = 11.5558, size = 178, normalized size = 0.31 \[ \frac{2 \sqrt{d \sin (e+f x)} (g \cos (e+f x))^{5/2} \left (a+b \sqrt{\sin ^2(e+f x)}\right ) \left (b F_1\left (\frac{5}{4};\frac{1}{4},1;\frac{9}{4};\cos ^2(e+f x),\frac{b^2 \cos ^2(e+f x)}{b^2-a^2}\right )-a F_1\left (\frac{5}{4};\frac{3}{4},1;\frac{9}{4};\cos ^2(e+f x),\frac{b^2 \cos ^2(e+f x)}{b^2-a^2}\right )\right )}{5 d f g \left (a^2-b^2\right ) \sqrt [4]{\sin ^2(e+f x)} (a+b \sin (e+f x))} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.273, size = 930, normalized size = 1.6 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (g \cos \left (f x + e\right )\right )^{\frac{3}{2}}}{{\left (b \sin \left (f x + e\right ) + a\right )} \sqrt{d \sin \left (f x + e\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (g \cos \left (f x + e\right )\right )^{\frac{3}{2}}}{{\left (b \sin \left (f x + e\right ) + a\right )} \sqrt{d \sin \left (f x + e\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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